CC/CV Step Down 5A Adjustable Power Module LED Driver with Voltmeter Ammeter Buck Battery Charging Module

This module is an adjustable step-down module. The output voltage can be changed by adjusting the blue adjustable resistance on the module. Input and output voltage difference is 1V, 0.8V voltage can be output.
The N-(input negative), IN+ (input positive), OUT-(output negative),
OUT+(output positive) indicated on the module must be connected correctly, otherwise the module will be damaged.

Modular nature:Non-isolated step down module
Rectifier mode:Asynchronous rectification
Input voltage:5V-30V
Output voltage:0.8V-29V
Output current:5A(Over 3A Heat Dissipation Need to be Strengthened)
Switch frequency:300KHz
Conversion efficiency:95%
Output ripple:50mV 20M banwidth
Load adjustment rate:+0.5%
Voltage adjustment rate:+2.5%
Working temperature:-40°C - +85°C

1: The module uses chips with high efficiency (95% higher and less calorific value), and can go to 5A current. The output current is controlled by TI operation by colleagues, so that the overall output is very stable.
2: This module uses a low ESR three- ocean filter capacitor, which can be as low as 50 mV ripple voltage.
3: This module uses machine patch and reflow welding.

Module name:Current voltage meter
measurement accuracy:0.10%
refresh rate:About 200 ms once
Display mode:Dual 4-bit 0.28"digital tube
Current range:0-5A
Voltage range:5-30V
Working current:less than 15mA
Storage temperature:-10°C~ +65°C
Display color:Red
Input impedance:50 milliohms

1: The LED digital tube used in this module is made of super high brightness, which can be clearly displayed even in the sun.
2: The module uses single chip sampling and display voltage, and carries out a lot of data processing in software to make the display accurate.
3: This module is the technology of front patch, and its volume is small.

APPLICATION:
Charging for lithium-ion batteries: When the voltage of lithium-ion batteries is relatively low, if they are charged directly with constant voltage, the charging current will be too large and the battery will be damaged because of the differential voltage, so the battery should be charged with constant current at the beginning, and the battery will be automatically switched back to constant voltage when the charging reaches a certain l